88(x^2-4x+4)=95

Solution for 88(x^2-4x+4)=95 equation:

88(x^2-4x+4)=95

We move all terms to the left:

88(x^2-4x+4)-(95)=0

We multiply parentheses

88x^2-352x+352-95=0

We add all the numbers together, and all the variables

88x^2-352x+257=0

a = 88; b = -352; c = +257;
Δ = b2-4ac
Δ = -3522-4·88·257
Δ = 33440
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{33440}=\sqrt{16*2090}=\sqrt{16}*\sqrt{2090}=4\sqrt{2090}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-352)-4\sqrt{2090}}{2*88}=\frac{352-4\sqrt{2090}}{176}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-352)+4\sqrt{2090}}{2*88}=\frac{352+4\sqrt{2090}}{176}
$